3.2.81 \(\int \frac {(a+b \tanh ^{-1}(\frac {c}{x^2}))^2}{x^6} \, dx\) [181]

Optimal. Leaf size=1337 \[ \frac {2 a b}{25 x^5}-\frac {2 a b}{15 c x^3}+\frac {2 a b}{5 c^2 x}-\frac {8 b^2}{15 c^2 x}+\frac {2 a b \text {ArcTan}\left (\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {4 b^2 \text {ArcTan}\left (\frac {x}{\sqrt {c}}\right )}{15 c^{5/2}}-\frac {i b^2 \text {ArcTan}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {4 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{15 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {2 b^2 \text {ArcTan}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{25 x^5}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{15 c x^3}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{5 c^2 x}-\frac {b^2 \text {ArcTan}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1-\frac {c}{x^2}\right )}{5 c^{5/2}}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{25 x^5}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{15 c x^3}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^2 x}+\frac {b \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^{5/2}}-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{20 x^5}-\frac {a b \log \left (1+\frac {c}{x^2}\right )}{5 x^5}-\frac {2 b^2 \log \left (1+\frac {c}{x^2}\right )}{15 c x^3}+\frac {b^2 \text {ArcTan}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )}{10 x^5}-\frac {b^2 \log ^2\left (1+\frac {c}{x^2}\right )}{20 x^5}-\frac {2 b^2 \text {ArcTan}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}+\frac {b^2 \text {ArcTan}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {(1+i) \left (\sqrt {c}-x\right )}{\sqrt {c}-i x}\right )}{5 c^{5/2}}+\frac {2 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c} \left (\sqrt {-c}-x\right )}{\left (\sqrt {-c}-\sqrt {c}\right ) \left (\sqrt {c}+x\right )}\right )}{5 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c} \left (\sqrt {-c}+x\right )}{\left (\sqrt {-c}+\sqrt {c}\right ) \left (\sqrt {c}+x\right )}\right )}{5 c^{5/2}}+\frac {b^2 \text {ArcTan}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {(1-i) \left (\sqrt {c}+x\right )}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {2 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}+\frac {i b^2 \text {PolyLog}\left (2,1-\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {i b^2 \text {PolyLog}\left (2,-1+\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {i b^2 \text {PolyLog}\left (2,1-\frac {(1+i) \left (\sqrt {c}-x\right )}{\sqrt {c}-i x}\right )}{10 c^{5/2}}-\frac {b^2 \text {PolyLog}\left (2,-\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {i b^2 \text {PolyLog}\left (2,-\frac {i x}{\sqrt {c}}\right )}{5 c^{5/2}}+\frac {i b^2 \text {PolyLog}\left (2,\frac {i x}{\sqrt {c}}\right )}{5 c^{5/2}}+\frac {b^2 \text {PolyLog}\left (2,\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {b^2 \text {PolyLog}\left (2,1-\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}+\frac {b^2 \text {PolyLog}\left (2,-1+\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}+\frac {b^2 \text {PolyLog}\left (2,1-\frac {2 \sqrt {c} \left (\sqrt {-c}-x\right )}{\left (\sqrt {-c}-\sqrt {c}\right ) \left (\sqrt {c}+x\right )}\right )}{10 c^{5/2}}+\frac {b^2 \text {PolyLog}\left (2,1-\frac {2 \sqrt {c} \left (\sqrt {-c}+x\right )}{\left (\sqrt {-c}+\sqrt {c}\right ) \left (\sqrt {c}+x\right )}\right )}{10 c^{5/2}}-\frac {i b^2 \text {PolyLog}\left (2,1-\frac {(1-i) \left (\sqrt {c}+x\right )}{\sqrt {c}-i x}\right )}{10 c^{5/2}} \]

[Out]

2/25*a*b/x^5-8/15*b^2/c^2/x+2/5*a*b*arctan(x/c^(1/2))/c^(5/2)+1/15*b^2*ln(1-c/x^2)/c/x^3-1/5*b^2*ln(1-c/x^2)/c
^2/x-1/5*b^2*arctan(x/c^(1/2))*ln(1-c/x^2)/c^(5/2)-1/15*b*(2*a-b*ln(1-c/x^2))/c/x^3-1/5*b*(2*a-b*ln(1-c/x^2))/
c^2/x+1/5*b*arctanh(x/c^(1/2))*(2*a-b*ln(1-c/x^2))/c^(5/2)-1/5*a*b*ln(1+c/x^2)/x^5-2/15*b^2*ln(1+c/x^2)/c/x^3+
1/5*b^2*arctan(x/c^(1/2))*ln(1+c/x^2)/c^(5/2)+1/5*b^2*arctanh(x/c^(1/2))*ln(1+c/x^2)/c^(5/2)+1/10*b^2*ln(1-c/x
^2)*ln(1+c/x^2)/x^5-2/5*b^2*arctan(x/c^(1/2))*ln(2*c^(1/2)/(-I*x+c^(1/2)))/c^(5/2)+1/5*b^2*arctan(x/c^(1/2))*l
n((1+I)*(-x+c^(1/2))/(-I*x+c^(1/2)))/c^(5/2)+2/5*b^2*arctanh(x/c^(1/2))*ln(2*c^(1/2)/(x+c^(1/2)))/c^(5/2)-1/5*
b^2*arctanh(x/c^(1/2))*ln(2*(-x+(-c)^(1/2))*c^(1/2)/((-c)^(1/2)-c^(1/2))/(x+c^(1/2)))/c^(5/2)+1/5*b^2*arctan(x
/c^(1/2))*ln((1-I)*(x+c^(1/2))/(-I*x+c^(1/2)))/c^(5/2)-1/5*b^2*arctanh(x/c^(1/2))*ln(2*(x+(-c)^(1/2))*c^(1/2)/
(x+c^(1/2))/((-c)^(1/2)+c^(1/2)))/c^(5/2)+2/5*b^2*arctan(x/c^(1/2))*ln(2-2*c^(1/2)/(-I*x+c^(1/2)))/c^(5/2)-2/5
*b^2*arctanh(x/c^(1/2))*ln(2-2*c^(1/2)/(x+c^(1/2)))/c^(5/2)-1/5*I*b^2*arctan(x/c^(1/2))^2/c^(5/2)-1/5*I*b^2*po
lylog(2,-I*x/c^(1/2))/c^(5/2)-1/5*I*b^2*polylog(2,-1+2*c^(1/2)/(-I*x+c^(1/2)))/c^(5/2)-1/10*I*b^2*polylog(2,1-
(1+I)*(-x+c^(1/2))/(-I*x+c^(1/2)))/c^(5/2)-1/10*I*b^2*polylog(2,1+(-1+I)*(x+c^(1/2))/(-I*x+c^(1/2)))/c^(5/2)+1
/5*I*b^2*polylog(2,I*x/c^(1/2))/c^(5/2)+1/5*I*b^2*polylog(2,1-2*c^(1/2)/(-I*x+c^(1/2)))/c^(5/2)-4/15*b^2*arcta
n(x/c^(1/2))/c^(5/2)+4/15*b^2*arctanh(x/c^(1/2))/c^(5/2)-1/5*b^2*arctanh(x/c^(1/2))^2/c^(5/2)-1/25*b^2*ln(1-c/
x^2)/x^5-1/25*b*(2*a-b*ln(1-c/x^2))/x^5-1/20*b^2*ln(1+c/x^2)^2/x^5-1/5*b^2*polylog(2,-x/c^(1/2))/c^(5/2)+1/5*b
^2*polylog(2,x/c^(1/2))/c^(5/2)-1/5*b^2*polylog(2,1-2*c^(1/2)/(x+c^(1/2)))/c^(5/2)+1/5*b^2*polylog(2,-1+2*c^(1
/2)/(x+c^(1/2)))/c^(5/2)+1/10*b^2*polylog(2,1-2*(-x+(-c)^(1/2))*c^(1/2)/((-c)^(1/2)-c^(1/2))/(x+c^(1/2)))/c^(5
/2)+1/10*b^2*polylog(2,1-2*(x+(-c)^(1/2))*c^(1/2)/(x+c^(1/2))/((-c)^(1/2)+c^(1/2)))/c^(5/2)-2/15*a*b/c/x^3+2/5
*a*b/c^2/x-1/20*(2*a-b*ln(1-c/x^2))^2/x^5

________________________________________________________________________________________

Rubi [A]
time = 2.04, antiderivative size = 1337, normalized size of antiderivative = 1.00, number of steps used = 130, number of rules used = 31, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.938, Rules used = {6045, 6042, 2507, 2526, 2505, 269, 331, 213, 212, 2520, 12, 266, 6820, 6135, 6079, 2497, 6874, 209, 30, 2637, 6139, 6031, 6057, 2449, 2352, 5048, 4940, 2438, 4966, 5044, 4988} \begin {gather*} -\frac {i \text {ArcTan}\left (\frac {x}{\sqrt {c}}\right )^2 b^2}{5 c^{5/2}}-\frac {\tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2 b^2}{5 c^{5/2}}-\frac {\log ^2\left (\frac {c}{x^2}+1\right ) b^2}{20 x^5}-\frac {4 \text {ArcTan}\left (\frac {x}{\sqrt {c}}\right ) b^2}{15 c^{5/2}}+\frac {4 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) b^2}{15 c^{5/2}}+\frac {2 \text {ArcTan}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right ) b^2}{5 c^{5/2}}-\frac {\text {ArcTan}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1-\frac {c}{x^2}\right ) b^2}{5 c^{5/2}}-\frac {\log \left (1-\frac {c}{x^2}\right ) b^2}{5 c^2 x}+\frac {\log \left (1-\frac {c}{x^2}\right ) b^2}{15 c x^3}-\frac {\log \left (1-\frac {c}{x^2}\right ) b^2}{25 x^5}+\frac {\text {ArcTan}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {c}{x^2}+1\right ) b^2}{5 c^{5/2}}+\frac {\tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {c}{x^2}+1\right ) b^2}{5 c^{5/2}}+\frac {\log \left (1-\frac {c}{x^2}\right ) \log \left (\frac {c}{x^2}+1\right ) b^2}{10 x^5}-\frac {2 \log \left (\frac {c}{x^2}+1\right ) b^2}{15 c x^3}-\frac {2 \text {ArcTan}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right ) b^2}{5 c^{5/2}}+\frac {\text {ArcTan}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {(1+i) \left (\sqrt {c}-x\right )}{\sqrt {c}-i x}\right ) b^2}{5 c^{5/2}}+\frac {2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c}}{x+\sqrt {c}}\right ) b^2}{5 c^{5/2}}-\frac {\tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c} \left (\sqrt {-c}-x\right )}{\left (\sqrt {-c}-\sqrt {c}\right ) \left (x+\sqrt {c}\right )}\right ) b^2}{5 c^{5/2}}-\frac {\tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c} \left (x+\sqrt {-c}\right )}{\left (\sqrt {-c}+\sqrt {c}\right ) \left (x+\sqrt {c}\right )}\right ) b^2}{5 c^{5/2}}+\frac {\text {ArcTan}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {(1-i) \left (x+\sqrt {c}\right )}{\sqrt {c}-i x}\right ) b^2}{5 c^{5/2}}-\frac {2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{x+\sqrt {c}}\right ) b^2}{5 c^{5/2}}+\frac {i \text {Li}_2\left (1-\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right ) b^2}{5 c^{5/2}}-\frac {i \text {Li}_2\left (\frac {2 \sqrt {c}}{\sqrt {c}-i x}-1\right ) b^2}{5 c^{5/2}}-\frac {i \text {Li}_2\left (1-\frac {(1+i) \left (\sqrt {c}-x\right )}{\sqrt {c}-i x}\right ) b^2}{10 c^{5/2}}-\frac {\text {Li}_2\left (-\frac {x}{\sqrt {c}}\right ) b^2}{5 c^{5/2}}-\frac {i \text {Li}_2\left (-\frac {i x}{\sqrt {c}}\right ) b^2}{5 c^{5/2}}+\frac {i \text {Li}_2\left (\frac {i x}{\sqrt {c}}\right ) b^2}{5 c^{5/2}}+\frac {\text {Li}_2\left (\frac {x}{\sqrt {c}}\right ) b^2}{5 c^{5/2}}-\frac {\text {Li}_2\left (1-\frac {2 \sqrt {c}}{x+\sqrt {c}}\right ) b^2}{5 c^{5/2}}+\frac {\text {Li}_2\left (\frac {2 \sqrt {c}}{x+\sqrt {c}}-1\right ) b^2}{5 c^{5/2}}+\frac {\text {Li}_2\left (1-\frac {2 \sqrt {c} \left (\sqrt {-c}-x\right )}{\left (\sqrt {-c}-\sqrt {c}\right ) \left (x+\sqrt {c}\right )}\right ) b^2}{10 c^{5/2}}+\frac {\text {Li}_2\left (1-\frac {2 \sqrt {c} \left (x+\sqrt {-c}\right )}{\left (\sqrt {-c}+\sqrt {c}\right ) \left (x+\sqrt {c}\right )}\right ) b^2}{10 c^{5/2}}-\frac {i \text {Li}_2\left (1-\frac {(1-i) \left (x+\sqrt {c}\right )}{\sqrt {c}-i x}\right ) b^2}{10 c^{5/2}}-\frac {8 b^2}{15 c^2 x}+\frac {2 a \text {ArcTan}\left (\frac {x}{\sqrt {c}}\right ) b}{5 c^{5/2}}+\frac {\tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right ) b}{5 c^{5/2}}-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right ) b}{5 c^2 x}-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right ) b}{15 c x^3}-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right ) b}{25 x^5}-\frac {a \log \left (\frac {c}{x^2}+1\right ) b}{5 x^5}+\frac {2 a b}{5 c^2 x}-\frac {2 a b}{15 c x^3}+\frac {2 a b}{25 x^5}-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{20 x^5} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a + b*ArcTanh[c/x^2])^2/x^6,x]

[Out]

(2*a*b)/(25*x^5) - (2*a*b)/(15*c*x^3) + (2*a*b)/(5*c^2*x) - (8*b^2)/(15*c^2*x) + (2*a*b*ArcTan[x/Sqrt[c]])/(5*
c^(5/2)) - (4*b^2*ArcTan[x/Sqrt[c]])/(15*c^(5/2)) - ((I/5)*b^2*ArcTan[x/Sqrt[c]]^2)/c^(5/2) + (4*b^2*ArcTanh[x
/Sqrt[c]])/(15*c^(5/2)) - (b^2*ArcTanh[x/Sqrt[c]]^2)/(5*c^(5/2)) + (2*b^2*ArcTan[x/Sqrt[c]]*Log[2 - (2*Sqrt[c]
)/(Sqrt[c] - I*x)])/(5*c^(5/2)) - (b^2*Log[1 - c/x^2])/(25*x^5) + (b^2*Log[1 - c/x^2])/(15*c*x^3) - (b^2*Log[1
- c/x^2])/(5*c^2*x) - (b^2*ArcTan[x/Sqrt[c]]*Log[1 - c/x^2])/(5*c^(5/2)) - (b*(2*a - b*Log[1 - c/x^2]))/(25*x
^5) - (b*(2*a - b*Log[1 - c/x^2]))/(15*c*x^3) - (b*(2*a - b*Log[1 - c/x^2]))/(5*c^2*x) + (b*ArcTanh[x/Sqrt[c]]
*(2*a - b*Log[1 - c/x^2]))/(5*c^(5/2)) - (2*a - b*Log[1 - c/x^2])^2/(20*x^5) - (a*b*Log[1 + c/x^2])/(5*x^5) -
(2*b^2*Log[1 + c/x^2])/(15*c*x^3) + (b^2*ArcTan[x/Sqrt[c]]*Log[1 + c/x^2])/(5*c^(5/2)) + (b^2*ArcTanh[x/Sqrt[c
]]*Log[1 + c/x^2])/(5*c^(5/2)) + (b^2*Log[1 - c/x^2]*Log[1 + c/x^2])/(10*x^5) - (b^2*Log[1 + c/x^2]^2)/(20*x^5
) - (2*b^2*ArcTan[x/Sqrt[c]]*Log[(2*Sqrt[c])/(Sqrt[c] - I*x)])/(5*c^(5/2)) + (b^2*ArcTan[x/Sqrt[c]]*Log[((1 +
I)*(Sqrt[c] - x))/(Sqrt[c] - I*x)])/(5*c^(5/2)) + (2*b^2*ArcTanh[x/Sqrt[c]]*Log[(2*Sqrt[c])/(Sqrt[c] + x)])/(5
*c^(5/2)) - (b^2*ArcTanh[x/Sqrt[c]]*Log[(2*Sqrt[c]*(Sqrt[-c] - x))/((Sqrt[-c] - Sqrt[c])*(Sqrt[c] + x))])/(5*c
^(5/2)) - (b^2*ArcTanh[x/Sqrt[c]]*Log[(2*Sqrt[c]*(Sqrt[-c] + x))/((Sqrt[-c] + Sqrt[c])*(Sqrt[c] + x))])/(5*c^(
5/2)) + (b^2*ArcTan[x/Sqrt[c]]*Log[((1 - I)*(Sqrt[c] + x))/(Sqrt[c] - I*x)])/(5*c^(5/2)) - (2*b^2*ArcTanh[x/Sq
rt[c]]*Log[2 - (2*Sqrt[c])/(Sqrt[c] + x)])/(5*c^(5/2)) + ((I/5)*b^2*PolyLog[2, 1 - (2*Sqrt[c])/(Sqrt[c] - I*x)
])/c^(5/2) - ((I/5)*b^2*PolyLog[2, -1 + (2*Sqrt[c])/(Sqrt[c] - I*x)])/c^(5/2) - ((I/10)*b^2*PolyLog[2, 1 - ((1
+ I)*(Sqrt[c] - x))/(Sqrt[c] - I*x)])/c^(5/2) - (b^2*PolyLog[2, -(x/Sqrt[c])])/(5*c^(5/2)) - ((I/5)*b^2*PolyL
og[2, ((-I)*x)/Sqrt[c]])/c^(5/2) + ((I/5)*b^2*PolyLog[2, (I*x)/Sqrt[c]])/c^(5/2) + (b^2*PolyLog[2, x/Sqrt[c]])
/(5*c^(5/2)) - (b^2*PolyLog[2, 1 - (2*Sqrt[c])/(Sqrt[c] + x)])/(5*c^(5/2)) + (b^2*PolyLog[2, -1 + (2*Sqrt[c])/
(Sqrt[c] + x)])/(5*c^(5/2)) + (b^2*PolyLog[2, 1 - (2*Sqrt[c]*(Sqrt[-c] - x))/((Sqrt[-c] - Sqrt[c])*(Sqrt[c] +
x))])/(10*c^(5/2)) + (b^2*PolyLog[2, 1 - (2*Sqrt[c]*(Sqrt[-c] + x))/((Sqrt[-c] + Sqrt[c])*(Sqrt[c] + x))])/(10
*c^(5/2)) - ((I/10)*b^2*PolyLog[2, 1 - ((1 - I)*(Sqrt[c] + x))/(Sqrt[c] - I*x)])/c^(5/2)

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 30

Int[(x_)^(m_.), x_Symbol] :> Simp[x^(m + 1)/(m + 1), x] /; FreeQ[m, x] && NeQ[m, -1]

Rule 209

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[b, 2]))*ArcTan[Rt[b, 2]*(x/Rt[a, 2])], x] /;
FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 212

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))*ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 213

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[b, 2])^(-1))*ArcTanh[Rt[b, 2]*(x/Rt[-a, 2])]
, x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (LtQ[a, 0] || GtQ[b, 0])

Rule 266

Int[(x_)^(m_.)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> Simp[Log[RemoveContent[a + b*x^n, x]]/(b*n), x] /; FreeQ
[{a, b, m, n}, x] && EqQ[m, n - 1]

Rule 269

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Int[x^(m + n*p)*(b + a/x^n)^p, x] /; FreeQ[{a, b, m
, n}, x] && IntegerQ[p] && NegQ[n]

Rule 331

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c*x)^(m + 1)*((a + b*x^n)^(p + 1)/(a*c
*(m + 1))), x] - Dist[b*((m + n*(p + 1) + 1)/(a*c^n*(m + 1))), Int[(c*x)^(m + n)*(a + b*x^n)^p, x], x] /; Free
Q[{a, b, c, p}, x] && IGtQ[n, 0] && LtQ[m, -1] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 2352

Int[Log[(c_.)*(x_)]/((d_) + (e_.)*(x_)), x_Symbol] :> Simp[(-e^(-1))*PolyLog[2, 1 - c*x], x] /; FreeQ[{c, d, e
}, x] && EqQ[e + c*d, 0]

Rule 2438

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> Simp[-PolyLog[2, (-c)*e*x^n]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rule 2449

Int[Log[(c_.)/((d_) + (e_.)*(x_))]/((f_) + (g_.)*(x_)^2), x_Symbol] :> Dist[-e/g, Subst[Int[Log[2*d*x]/(1 - 2*
d*x), x], x, 1/(d + e*x)], x] /; FreeQ[{c, d, e, f, g}, x] && EqQ[c, 2*d] && EqQ[e^2*f + d^2*g, 0]

Rule 2497

Int[Log[u_]*(Pq_)^(m_.), x_Symbol] :> With[{C = FullSimplify[Pq^m*((1 - u)/D[u, x])]}, Simp[C*PolyLog[2, 1 - u
], x] /; FreeQ[C, x]] /; IntegerQ[m] && PolyQ[Pq, x] && RationalFunctionQ[u, x] && LeQ[RationalFunctionExponen
ts[u, x][[2]], Expon[Pq, x]]

Rule 2505

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))*((f_.)*(x_))^(m_.), x_Symbol] :> Simp[(f*x)^(m +
1)*((a + b*Log[c*(d + e*x^n)^p])/(f*(m + 1))), x] - Dist[b*e*n*(p/(f*(m + 1))), Int[x^(n - 1)*((f*x)^(m + 1)/
(d + e*x^n)), x], x] /; FreeQ[{a, b, c, d, e, f, m, n, p}, x] && NeQ[m, -1]

Rule 2507

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))^(q_)*((f_.)*(x_))^(m_.), x_Symbol] :> Simp[(f*x)
^(m + 1)*((a + b*Log[c*(d + e*x^n)^p])^q/(f*(m + 1))), x] - Dist[b*e*n*p*(q/(f^n*(m + 1))), Int[(f*x)^(m + n)*
((a + b*Log[c*(d + e*x^n)^p])^(q - 1)/(d + e*x^n)), x], x] /; FreeQ[{a, b, c, d, e, f, m, p}, x] && IGtQ[q, 1]
&& IntegerQ[n] && NeQ[m, -1]

Rule 2520

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))/((f_) + (g_.)*(x_)^2), x_Symbol] :> With[{u = In
tHide[1/(f + g*x^2), x]}, Simp[u*(a + b*Log[c*(d + e*x^n)^p]), x] - Dist[b*e*n*p, Int[u*(x^(n - 1)/(d + e*x^n)
), x], x]] /; FreeQ[{a, b, c, d, e, f, g, n, p}, x] && IntegerQ[n]

Rule 2526

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))^(q_.)*(x_)^(m_.)*((f_) + (g_.)*(x_)^(s_))^(r_.),
x_Symbol] :> Int[ExpandIntegrand[(a + b*Log[c*(d + e*x^n)^p])^q, x^m*(f + g*x^s)^r, x], x] /; FreeQ[{a, b, c,
d, e, f, g, m, n, p, q, r, s}, x] && IGtQ[q, 0] && IntegerQ[m] && IntegerQ[r] && IntegerQ[s]

Rule 2637

Int[Log[v_]*Log[w_]*(u_), x_Symbol] :> With[{z = IntHide[u, x]}, Dist[Log[v]*Log[w], z, x] + (-Int[SimplifyInt
egrand[z*Log[w]*(D[v, x]/v), x], x] - Int[SimplifyIntegrand[z*Log[v]*(D[w, x]/w), x], x]) /; InverseFunctionFr
eeQ[z, x]] /; InverseFunctionFreeQ[v, x] && InverseFunctionFreeQ[w, x]

Rule 4940

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))/(x_), x_Symbol] :> Simp[a*Log[x], x] + (Dist[I*(b/2), Int[Log[1 - I*c*x
]/x, x], x] - Dist[I*(b/2), Int[Log[1 + I*c*x]/x, x], x]) /; FreeQ[{a, b, c}, x]

Rule 4966

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))/((d_) + (e_.)*(x_)), x_Symbol] :> Simp[(-(a + b*ArcTan[c*x]))*(Log[2/(1
- I*c*x)]/e), x] + (Dist[b*(c/e), Int[Log[2/(1 - I*c*x)]/(1 + c^2*x^2), x], x] - Dist[b*(c/e), Int[Log[2*c*((
d + e*x)/((c*d + I*e)*(1 - I*c*x)))]/(1 + c^2*x^2), x], x] + Simp[(a + b*ArcTan[c*x])*(Log[2*c*((d + e*x)/((c*
d + I*e)*(1 - I*c*x)))]/e), x]) /; FreeQ[{a, b, c, d, e}, x] && NeQ[c^2*d^2 + e^2, 0]

Rule 4988

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)/((x_)*((d_) + (e_.)*(x_))), x_Symbol] :> Simp[(a + b*ArcTan[c*x])
^p*(Log[2 - 2/(1 + e*(x/d))]/d), x] - Dist[b*c*(p/d), Int[(a + b*ArcTan[c*x])^(p - 1)*(Log[2 - 2/(1 + e*(x/d))
]/(1 + c^2*x^2)), x], x] /; FreeQ[{a, b, c, d, e}, x] && IGtQ[p, 0] && EqQ[c^2*d^2 + e^2, 0]

Rule 5044

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)/((x_)*((d_) + (e_.)*(x_)^2)), x_Symbol] :> Simp[(-I)*((a + b*ArcT
an[c*x])^(p + 1)/(b*d*(p + 1))), x] + Dist[I/d, Int[(a + b*ArcTan[c*x])^p/(x*(I + c*x)), x], x] /; FreeQ[{a, b
, c, d, e}, x] && EqQ[e, c^2*d] && GtQ[p, 0]

Rule 5048

Int[(((a_.) + ArcTan[(c_.)*(x_)]*(b_.))*(x_)^(m_.))/((d_) + (e_.)*(x_)^2), x_Symbol] :> Int[ExpandIntegrand[a
+ b*ArcTan[c*x], x^m/(d + e*x^2), x], x] /; FreeQ[{a, b, c, d, e}, x] && IntegerQ[m] &&  !(EqQ[m, 1] && NeQ[a,
0])

Rule 6031

Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))/(x_), x_Symbol] :> Simp[a*Log[x], x] + (-Simp[(b/2)*PolyLog[2, (-c)*x]
, x] + Simp[(b/2)*PolyLog[2, c*x], x]) /; FreeQ[{a, b, c}, x]

Rule 6042

Int[((a_.) + ArcCoth[(c_.)*(x_)^(n_)]*(b_.))^(p_)*(x_)^(m_.), x_Symbol] :> Int[ExpandIntegrand[x^m*(a + b*(Log
[1 + 1/(x^n*c)]/2) - b*(Log[1 - 1/(x^n*c)]/2))^p, x], x] /; FreeQ[{a, b, c}, x] && IGtQ[p, 1] && IGtQ[n, 0] &&
IntegerQ[m]

Rule 6045

Int[((a_.) + ArcTanh[(c_.)*(x_)^(n_)]*(b_.))^(p_)*(x_)^(m_.), x_Symbol] :> Int[x^m*(a + b*ArcCoth[1/(x^n*c)])^
p, x] /; FreeQ[{a, b, c, m}, x] && IGtQ[p, 1] && ILtQ[n, 0]

Rule 6057

Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))/((d_) + (e_.)*(x_)), x_Symbol] :> Simp[(-(a + b*ArcTanh[c*x]))*(Log[2/
(1 + c*x)]/e), x] + (Dist[b*(c/e), Int[Log[2/(1 + c*x)]/(1 - c^2*x^2), x], x] - Dist[b*(c/e), Int[Log[2*c*((d
+ e*x)/((c*d + e)*(1 + c*x)))]/(1 - c^2*x^2), x], x] + Simp[(a + b*ArcTanh[c*x])*(Log[2*c*((d + e*x)/((c*d + e
)*(1 + c*x)))]/e), x]) /; FreeQ[{a, b, c, d, e}, x] && NeQ[c^2*d^2 - e^2, 0]

Rule 6079

Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)/((x_)*((d_) + (e_.)*(x_))), x_Symbol] :> Simp[(a + b*ArcTanh[c*x
])^p*(Log[2 - 2/(1 + e*(x/d))]/d), x] - Dist[b*c*(p/d), Int[(a + b*ArcTanh[c*x])^(p - 1)*(Log[2 - 2/(1 + e*(x/
d))]/(1 - c^2*x^2)), x], x] /; FreeQ[{a, b, c, d, e}, x] && IGtQ[p, 0] && EqQ[c^2*d^2 - e^2, 0]

Rule 6135

Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)/((x_)*((d_) + (e_.)*(x_)^2)), x_Symbol] :> Simp[(a + b*ArcTanh[c
*x])^(p + 1)/(b*d*(p + 1)), x] + Dist[1/d, Int[(a + b*ArcTanh[c*x])^p/(x*(1 + c*x)), x], x] /; FreeQ[{a, b, c,
d, e}, x] && EqQ[c^2*d + e, 0] && GtQ[p, 0]

Rule 6139

Int[(((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))*(x_)^(m_.))/((d_) + (e_.)*(x_)^2), x_Symbol] :> Int[ExpandIntegrand[a
+ b*ArcTanh[c*x], x^m/(d + e*x^2), x], x] /; FreeQ[{a, b, c, d, e}, x] && IntegerQ[m] &&  !(EqQ[m, 1] && NeQ[
a, 0])

Rule 6820

Int[u_, x_Symbol] :> With[{v = SimplifyIntegrand[u, x]}, Int[v, x] /; SimplerIntegrandQ[v, u, x]]

Rule 6874

Int[u_, x_Symbol] :> With[{v = ExpandIntegrand[u, x]}, Int[v, x] /; SumQ[v]]

Rubi steps

\begin {align*} \int \frac {\left (a+b \tanh ^{-1}\left (\frac {c}{x^2}\right )\right )^2}{x^6} \, dx &=\int \left (\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{4 x^6}-\frac {b \left (-2 a+b \log \left (1-\frac {c}{x^2}\right )\right ) \log \left (1+\frac {c}{x^2}\right )}{2 x^6}+\frac {b^2 \log ^2\left (1+\frac {c}{x^2}\right )}{4 x^6}\right ) \, dx\\ &=\frac {1}{4} \int \frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{x^6} \, dx-\frac {1}{2} b \int \frac {\left (-2 a+b \log \left (1-\frac {c}{x^2}\right )\right ) \log \left (1+\frac {c}{x^2}\right )}{x^6} \, dx+\frac {1}{4} b^2 \int \frac {\log ^2\left (1+\frac {c}{x^2}\right )}{x^6} \, dx\\ &=-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{20 x^5}-\frac {b^2 \log ^2\left (1+\frac {c}{x^2}\right )}{20 x^5}-\frac {1}{2} b \int \left (-\frac {2 a \log \left (1+\frac {c}{x^2}\right )}{x^6}+\frac {b \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )}{x^6}\right ) \, dx-\frac {1}{5} (b c) \int \frac {2 a-b \log \left (1-\frac {c}{x^2}\right )}{\left (1-\frac {c}{x^2}\right ) x^8} \, dx-\frac {1}{5} \left (b^2 c\right ) \int \frac {\log \left (1+\frac {c}{x^2}\right )}{\left (1+\frac {c}{x^2}\right ) x^8} \, dx\\ &=-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{20 x^5}-\frac {b^2 \log ^2\left (1+\frac {c}{x^2}\right )}{20 x^5}+(a b) \int \frac {\log \left (1+\frac {c}{x^2}\right )}{x^6} \, dx-\frac {1}{2} b^2 \int \frac {\log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )}{x^6} \, dx-\frac {1}{5} (b c) \int \left (-\frac {2 a-b \log \left (1-\frac {c}{x^2}\right )}{c x^6}-\frac {2 a-b \log \left (1-\frac {c}{x^2}\right )}{c^2 x^4}-\frac {2 a-b \log \left (1-\frac {c}{x^2}\right )}{c^3 x^2}-\frac {2 a-b \log \left (1-\frac {c}{x^2}\right )}{c^3 \left (c-x^2\right )}\right ) \, dx-\frac {1}{5} \left (b^2 c\right ) \int \left (\frac {\log \left (1+\frac {c}{x^2}\right )}{c x^6}-\frac {\log \left (1+\frac {c}{x^2}\right )}{c^2 x^4}+\frac {\log \left (1+\frac {c}{x^2}\right )}{c^3 x^2}-\frac {\log \left (1+\frac {c}{x^2}\right )}{c^3 \left (c+x^2\right )}\right ) \, dx\\ &=-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{20 x^5}-\frac {a b \log \left (1+\frac {c}{x^2}\right )}{5 x^5}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )}{10 x^5}-\frac {b^2 \log ^2\left (1+\frac {c}{x^2}\right )}{20 x^5}+\frac {1}{5} b \int \frac {2 a-b \log \left (1-\frac {c}{x^2}\right )}{x^6} \, dx-\frac {1}{5} b^2 \int \frac {\log \left (1+\frac {c}{x^2}\right )}{x^6} \, dx+\frac {1}{2} b^2 \int \frac {2 c \log \left (1-\frac {c}{x^2}\right )}{5 x^6 \left (c+x^2\right )} \, dx+\frac {1}{2} b^2 \int \frac {2 c \log \left (1+\frac {c}{x^2}\right )}{5 x^6 \left (c-x^2\right )} \, dx+\frac {b \int \frac {2 a-b \log \left (1-\frac {c}{x^2}\right )}{x^2} \, dx}{5 c^2}+\frac {b \int \frac {2 a-b \log \left (1-\frac {c}{x^2}\right )}{c-x^2} \, dx}{5 c^2}-\frac {b^2 \int \frac {\log \left (1+\frac {c}{x^2}\right )}{x^2} \, dx}{5 c^2}+\frac {b^2 \int \frac {\log \left (1+\frac {c}{x^2}\right )}{c+x^2} \, dx}{5 c^2}+\frac {b \int \frac {2 a-b \log \left (1-\frac {c}{x^2}\right )}{x^4} \, dx}{5 c}+\frac {b^2 \int \frac {\log \left (1+\frac {c}{x^2}\right )}{x^4} \, dx}{5 c}-\frac {1}{5} (2 a b c) \int \frac {1}{\left (1+\frac {c}{x^2}\right ) x^8} \, dx\\ &=-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{25 x^5}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{15 c x^3}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^2 x}+\frac {b \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^{5/2}}-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{20 x^5}-\frac {a b \log \left (1+\frac {c}{x^2}\right )}{5 x^5}+\frac {b^2 \log \left (1+\frac {c}{x^2}\right )}{25 x^5}-\frac {b^2 \log \left (1+\frac {c}{x^2}\right )}{15 c x^3}+\frac {b^2 \log \left (1+\frac {c}{x^2}\right )}{5 c^2 x}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )}{10 x^5}-\frac {b^2 \log ^2\left (1+\frac {c}{x^2}\right )}{20 x^5}-\frac {1}{15} \left (2 b^2\right ) \int \frac {1}{\left (1-\frac {c}{x^2}\right ) x^6} \, dx-\frac {1}{15} \left (2 b^2\right ) \int \frac {1}{\left (1+\frac {c}{x^2}\right ) x^6} \, dx-\frac {\left (2 b^2\right ) \int \frac {1}{\left (1-\frac {c}{x^2}\right ) x^4} \, dx}{5 c}+\frac {\left (2 b^2\right ) \int \frac {1}{\left (1+\frac {c}{x^2}\right ) x^4} \, dx}{5 c}+\frac {\left (2 b^2\right ) \int \frac {\tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{\sqrt {c} \left (1+\frac {c}{x^2}\right ) x^3} \, dx}{5 c}+\frac {\left (2 b^2\right ) \int \frac {\tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{\sqrt {c} \left (1-\frac {c}{x^2}\right ) x^3} \, dx}{5 c}-\frac {1}{5} (2 a b c) \int \frac {1}{x^6 \left (c+x^2\right )} \, dx-\frac {1}{25} \left (2 b^2 c\right ) \int \frac {1}{\left (1-\frac {c}{x^2}\right ) x^8} \, dx+\frac {1}{25} \left (2 b^2 c\right ) \int \frac {1}{\left (1+\frac {c}{x^2}\right ) x^8} \, dx+\frac {1}{5} \left (b^2 c\right ) \int \frac {\log \left (1-\frac {c}{x^2}\right )}{x^6 \left (c+x^2\right )} \, dx+\frac {1}{5} \left (b^2 c\right ) \int \frac {\log \left (1+\frac {c}{x^2}\right )}{x^6 \left (c-x^2\right )} \, dx\\ &=\frac {2 a b}{25 x^5}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{25 x^5}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{15 c x^3}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^2 x}+\frac {b \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^{5/2}}-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{20 x^5}-\frac {a b \log \left (1+\frac {c}{x^2}\right )}{5 x^5}+\frac {b^2 \log \left (1+\frac {c}{x^2}\right )}{25 x^5}-\frac {b^2 \log \left (1+\frac {c}{x^2}\right )}{15 c x^3}+\frac {b^2 \log \left (1+\frac {c}{x^2}\right )}{5 c^2 x}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )}{10 x^5}-\frac {b^2 \log ^2\left (1+\frac {c}{x^2}\right )}{20 x^5}+\frac {1}{5} (2 a b) \int \frac {1}{x^4 \left (c+x^2\right )} \, dx-\frac {1}{15} \left (2 b^2\right ) \int \frac {1}{x^4 \left (-c+x^2\right )} \, dx-\frac {1}{15} \left (2 b^2\right ) \int \frac {1}{x^4 \left (c+x^2\right )} \, dx+\frac {\left (2 b^2\right ) \int \frac {\tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{\left (1+\frac {c}{x^2}\right ) x^3} \, dx}{5 c^{3/2}}+\frac {\left (2 b^2\right ) \int \frac {\tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{\left (1-\frac {c}{x^2}\right ) x^3} \, dx}{5 c^{3/2}}-\frac {\left (2 b^2\right ) \int \frac {1}{x^2 \left (-c+x^2\right )} \, dx}{5 c}+\frac {\left (2 b^2\right ) \int \frac {1}{x^2 \left (c+x^2\right )} \, dx}{5 c}-\frac {1}{25} \left (2 b^2 c\right ) \int \frac {1}{x^6 \left (-c+x^2\right )} \, dx+\frac {1}{25} \left (2 b^2 c\right ) \int \frac {1}{x^6 \left (c+x^2\right )} \, dx+\frac {1}{5} \left (b^2 c\right ) \int \left (\frac {\log \left (1-\frac {c}{x^2}\right )}{c x^6}-\frac {\log \left (1-\frac {c}{x^2}\right )}{c^2 x^4}+\frac {\log \left (1-\frac {c}{x^2}\right )}{c^3 x^2}-\frac {\log \left (1-\frac {c}{x^2}\right )}{c^3 \left (c+x^2\right )}\right ) \, dx+\frac {1}{5} \left (b^2 c\right ) \int \left (\frac {\log \left (1+\frac {c}{x^2}\right )}{c x^6}+\frac {\log \left (1+\frac {c}{x^2}\right )}{c^2 x^4}+\frac {\log \left (1+\frac {c}{x^2}\right )}{c^3 x^2}+\frac {\log \left (1+\frac {c}{x^2}\right )}{c^3 \left (c-x^2\right )}\right ) \, dx\\ &=\frac {2 a b}{25 x^5}-\frac {4 b^2}{125 x^5}-\frac {2 a b}{15 c x^3}-\frac {4 b^2}{5 c^2 x}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{25 x^5}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{15 c x^3}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^2 x}+\frac {b \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^{5/2}}-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{20 x^5}-\frac {a b \log \left (1+\frac {c}{x^2}\right )}{5 x^5}+\frac {b^2 \log \left (1+\frac {c}{x^2}\right )}{25 x^5}-\frac {b^2 \log \left (1+\frac {c}{x^2}\right )}{15 c x^3}+\frac {b^2 \log \left (1+\frac {c}{x^2}\right )}{5 c^2 x}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )}{10 x^5}-\frac {b^2 \log ^2\left (1+\frac {c}{x^2}\right )}{20 x^5}-\frac {1}{25} \left (2 b^2\right ) \int \frac {1}{x^4 \left (-c+x^2\right )} \, dx-\frac {1}{25} \left (2 b^2\right ) \int \frac {1}{x^4 \left (c+x^2\right )} \, dx+\frac {1}{5} b^2 \int \frac {\log \left (1-\frac {c}{x^2}\right )}{x^6} \, dx+\frac {1}{5} b^2 \int \frac {\log \left (1+\frac {c}{x^2}\right )}{x^6} \, dx+\frac {b^2 \int \frac {\log \left (1-\frac {c}{x^2}\right )}{x^2} \, dx}{5 c^2}-\frac {b^2 \int \frac {\log \left (1-\frac {c}{x^2}\right )}{c+x^2} \, dx}{5 c^2}+\frac {b^2 \int \frac {\log \left (1+\frac {c}{x^2}\right )}{x^2} \, dx}{5 c^2}+\frac {b^2 \int \frac {\log \left (1+\frac {c}{x^2}\right )}{c-x^2} \, dx}{5 c^2}-\frac {\left (2 b^2\right ) \int \frac {1}{-c+x^2} \, dx}{5 c^2}-\frac {\left (2 b^2\right ) \int \frac {1}{c+x^2} \, dx}{5 c^2}+\frac {\left (2 b^2\right ) \int \frac {\tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{x \left (c+x^2\right )} \, dx}{5 c^{3/2}}+\frac {\left (2 b^2\right ) \int \frac {\tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{x \left (-c+x^2\right )} \, dx}{5 c^{3/2}}-\frac {(2 a b) \int \frac {1}{x^2 \left (c+x^2\right )} \, dx}{5 c}-\frac {\left (2 b^2\right ) \int \frac {1}{x^2 \left (-c+x^2\right )} \, dx}{15 c}+\frac {\left (2 b^2\right ) \int \frac {1}{x^2 \left (c+x^2\right )} \, dx}{15 c}-\frac {b^2 \int \frac {\log \left (1-\frac {c}{x^2}\right )}{x^4} \, dx}{5 c}+\frac {b^2 \int \frac {\log \left (1+\frac {c}{x^2}\right )}{x^4} \, dx}{5 c}\\ &=\frac {2 a b}{25 x^5}-\frac {4 b^2}{125 x^5}-\frac {2 a b}{15 c x^3}+\frac {2 a b}{5 c^2 x}-\frac {16 b^2}{15 c^2 x}-\frac {2 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {i b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {2 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{25 x^5}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{15 c x^3}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{5 c^2 x}-\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1-\frac {c}{x^2}\right )}{5 c^{5/2}}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{25 x^5}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{15 c x^3}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^2 x}+\frac {b \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^{5/2}}-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{20 x^5}-\frac {a b \log \left (1+\frac {c}{x^2}\right )}{5 x^5}-\frac {2 b^2 \log \left (1+\frac {c}{x^2}\right )}{15 c x^3}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )}{10 x^5}-\frac {b^2 \log ^2\left (1+\frac {c}{x^2}\right )}{20 x^5}-\frac {1}{15} \left (2 b^2\right ) \int \frac {1}{\left (1-\frac {c}{x^2}\right ) x^6} \, dx-\frac {1}{15} \left (2 b^2\right ) \int \frac {1}{\left (1+\frac {c}{x^2}\right ) x^6} \, dx+\frac {\left (2 i b^2\right ) \int \frac {\tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{x \left (i+\frac {x}{\sqrt {c}}\right )} \, dx}{5 c^{5/2}}-\frac {\left (2 b^2\right ) \int \frac {\tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{x \left (1+\frac {x}{\sqrt {c}}\right )} \, dx}{5 c^{5/2}}+\frac {(2 a b) \int \frac {1}{c+x^2} \, dx}{5 c^2}-\frac {\left (2 b^2\right ) \int \frac {1}{-c+x^2} \, dx}{15 c^2}-\frac {\left (2 b^2\right ) \int \frac {1}{c+x^2} \, dx}{15 c^2}-\frac {\left (2 b^2\right ) \int \frac {1}{x^2 \left (-c+x^2\right )} \, dx}{25 c}+\frac {\left (2 b^2\right ) \int \frac {1}{x^2 \left (c+x^2\right )} \, dx}{25 c}+\frac {\left (2 b^2\right ) \int \frac {1}{\left (1-\frac {c}{x^2}\right ) x^4} \, dx}{5 c}-\frac {\left (2 b^2\right ) \int \frac {1}{\left (1+\frac {c}{x^2}\right ) x^4} \, dx}{5 c}+\frac {\left (2 b^2\right ) \int \frac {\tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{\sqrt {c} \left (1-\frac {c}{x^2}\right ) x^3} \, dx}{5 c}+\frac {\left (2 b^2\right ) \int \frac {\tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{\sqrt {c} \left (1+\frac {c}{x^2}\right ) x^3} \, dx}{5 c}+\frac {1}{25} \left (2 b^2 c\right ) \int \frac {1}{\left (1-\frac {c}{x^2}\right ) x^8} \, dx-\frac {1}{25} \left (2 b^2 c\right ) \int \frac {1}{\left (1+\frac {c}{x^2}\right ) x^8} \, dx\\ &=\frac {2 a b}{25 x^5}-\frac {4 b^2}{125 x^5}-\frac {2 a b}{15 c x^3}+\frac {2 a b}{5 c^2 x}-\frac {92 b^2}{75 c^2 x}+\frac {2 a b \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {8 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{15 c^{5/2}}-\frac {i b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {8 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{15 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {2 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{25 x^5}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{15 c x^3}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{5 c^2 x}-\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1-\frac {c}{x^2}\right )}{5 c^{5/2}}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{25 x^5}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{15 c x^3}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^2 x}+\frac {b \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^{5/2}}-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{20 x^5}-\frac {a b \log \left (1+\frac {c}{x^2}\right )}{5 x^5}-\frac {2 b^2 \log \left (1+\frac {c}{x^2}\right )}{15 c x^3}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )}{10 x^5}-\frac {b^2 \log ^2\left (1+\frac {c}{x^2}\right )}{20 x^5}-\frac {2 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}-\frac {1}{15} \left (2 b^2\right ) \int \frac {1}{x^4 \left (-c+x^2\right )} \, dx-\frac {1}{15} \left (2 b^2\right ) \int \frac {1}{x^4 \left (c+x^2\right )} \, dx-\frac {\left (2 b^2\right ) \int \frac {\log \left (2-\frac {2}{1-\frac {i x}{\sqrt {c}}}\right )}{1+\frac {x^2}{c}} \, dx}{5 c^3}+\frac {\left (2 b^2\right ) \int \frac {\log \left (2-\frac {2}{1+\frac {x}{\sqrt {c}}}\right )}{1-\frac {x^2}{c}} \, dx}{5 c^3}-\frac {\left (2 b^2\right ) \int \frac {1}{-c+x^2} \, dx}{25 c^2}-\frac {\left (2 b^2\right ) \int \frac {1}{c+x^2} \, dx}{25 c^2}+\frac {\left (2 b^2\right ) \int \frac {\tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{\left (1-\frac {c}{x^2}\right ) x^3} \, dx}{5 c^{3/2}}+\frac {\left (2 b^2\right ) \int \frac {\tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{\left (1+\frac {c}{x^2}\right ) x^3} \, dx}{5 c^{3/2}}+\frac {\left (2 b^2\right ) \int \frac {1}{x^2 \left (-c+x^2\right )} \, dx}{5 c}-\frac {\left (2 b^2\right ) \int \frac {1}{x^2 \left (c+x^2\right )} \, dx}{5 c}+\frac {1}{25} \left (2 b^2 c\right ) \int \frac {1}{x^6 \left (-c+x^2\right )} \, dx-\frac {1}{25} \left (2 b^2 c\right ) \int \frac {1}{x^6 \left (c+x^2\right )} \, dx\\ &=\frac {2 a b}{25 x^5}-\frac {2 a b}{15 c x^3}+\frac {2 a b}{5 c^2 x}-\frac {32 b^2}{75 c^2 x}+\frac {2 a b \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {46 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{75 c^{5/2}}-\frac {i b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {46 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{75 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {2 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{25 x^5}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{15 c x^3}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{5 c^2 x}-\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1-\frac {c}{x^2}\right )}{5 c^{5/2}}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{25 x^5}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{15 c x^3}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^2 x}+\frac {b \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^{5/2}}-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{20 x^5}-\frac {a b \log \left (1+\frac {c}{x^2}\right )}{5 x^5}-\frac {2 b^2 \log \left (1+\frac {c}{x^2}\right )}{15 c x^3}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )}{10 x^5}-\frac {b^2 \log ^2\left (1+\frac {c}{x^2}\right )}{20 x^5}-\frac {2 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}-\frac {i b^2 \text {Li}_2\left (-1+\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}+\frac {b^2 \text {Li}_2\left (-1+\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}+\frac {1}{25} \left (2 b^2\right ) \int \frac {1}{x^4 \left (-c+x^2\right )} \, dx+\frac {1}{25} \left (2 b^2\right ) \int \frac {1}{x^4 \left (c+x^2\right )} \, dx+\frac {\left (2 b^2\right ) \int \frac {1}{-c+x^2} \, dx}{5 c^2}+\frac {\left (2 b^2\right ) \int \frac {1}{c+x^2} \, dx}{5 c^2}+\frac {\left (2 b^2\right ) \int \frac {\tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{x \left (-c+x^2\right )} \, dx}{5 c^{3/2}}+\frac {\left (2 b^2\right ) \int \frac {\tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{x \left (c+x^2\right )} \, dx}{5 c^{3/2}}-\frac {\left (2 b^2\right ) \int \frac {1}{x^2 \left (-c+x^2\right )} \, dx}{15 c}+\frac {\left (2 b^2\right ) \int \frac {1}{x^2 \left (c+x^2\right )} \, dx}{15 c}\\ &=\frac {2 a b}{25 x^5}-\frac {2 a b}{15 c x^3}+\frac {2 a b}{5 c^2 x}-\frac {52 b^2}{75 c^2 x}+\frac {2 a b \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {16 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{75 c^{5/2}}-\frac {i b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {16 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{75 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {2 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{25 x^5}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{15 c x^3}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{5 c^2 x}-\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1-\frac {c}{x^2}\right )}{5 c^{5/2}}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{25 x^5}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{15 c x^3}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^2 x}+\frac {b \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^{5/2}}-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{20 x^5}-\frac {a b \log \left (1+\frac {c}{x^2}\right )}{5 x^5}-\frac {2 b^2 \log \left (1+\frac {c}{x^2}\right )}{15 c x^3}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )}{10 x^5}-\frac {b^2 \log ^2\left (1+\frac {c}{x^2}\right )}{20 x^5}-\frac {2 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}-\frac {i b^2 \text {Li}_2\left (-1+\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}+\frac {b^2 \text {Li}_2\left (-1+\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}-\frac {\left (2 b^2\right ) \int \frac {1}{-c+x^2} \, dx}{15 c^2}-\frac {\left (2 b^2\right ) \int \frac {1}{c+x^2} \, dx}{15 c^2}+\frac {\left (2 b^2\right ) \int \left (-\frac {\tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{c x}-\frac {x \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{c \left (c-x^2\right )}\right ) \, dx}{5 c^{3/2}}+\frac {\left (2 b^2\right ) \int \left (\frac {\tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{c x}-\frac {x \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{c \left (c+x^2\right )}\right ) \, dx}{5 c^{3/2}}+\frac {\left (2 b^2\right ) \int \frac {1}{x^2 \left (-c+x^2\right )} \, dx}{25 c}-\frac {\left (2 b^2\right ) \int \frac {1}{x^2 \left (c+x^2\right )} \, dx}{25 c}\\ &=\frac {2 a b}{25 x^5}-\frac {2 a b}{15 c x^3}+\frac {2 a b}{5 c^2 x}-\frac {8 b^2}{15 c^2 x}+\frac {2 a b \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {26 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{75 c^{5/2}}-\frac {i b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {26 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{75 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {2 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{25 x^5}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{15 c x^3}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{5 c^2 x}-\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1-\frac {c}{x^2}\right )}{5 c^{5/2}}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{25 x^5}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{15 c x^3}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^2 x}+\frac {b \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^{5/2}}-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{20 x^5}-\frac {a b \log \left (1+\frac {c}{x^2}\right )}{5 x^5}-\frac {2 b^2 \log \left (1+\frac {c}{x^2}\right )}{15 c x^3}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )}{10 x^5}-\frac {b^2 \log ^2\left (1+\frac {c}{x^2}\right )}{20 x^5}-\frac {2 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}-\frac {i b^2 \text {Li}_2\left (-1+\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}+\frac {b^2 \text {Li}_2\left (-1+\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}-\frac {\left (2 b^2\right ) \int \frac {\tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{x} \, dx}{5 c^{5/2}}-\frac {\left (2 b^2\right ) \int \frac {x \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{c-x^2} \, dx}{5 c^{5/2}}+\frac {\left (2 b^2\right ) \int \frac {\tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{x} \, dx}{5 c^{5/2}}-\frac {\left (2 b^2\right ) \int \frac {x \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{c+x^2} \, dx}{5 c^{5/2}}+\frac {\left (2 b^2\right ) \int \frac {1}{-c+x^2} \, dx}{25 c^2}+\frac {\left (2 b^2\right ) \int \frac {1}{c+x^2} \, dx}{25 c^2}\\ &=\frac {2 a b}{25 x^5}-\frac {2 a b}{15 c x^3}+\frac {2 a b}{5 c^2 x}-\frac {8 b^2}{15 c^2 x}+\frac {2 a b \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {4 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{15 c^{5/2}}-\frac {i b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {4 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{15 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {2 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{25 x^5}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{15 c x^3}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{5 c^2 x}-\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1-\frac {c}{x^2}\right )}{5 c^{5/2}}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{25 x^5}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{15 c x^3}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^2 x}+\frac {b \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^{5/2}}-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{20 x^5}-\frac {a b \log \left (1+\frac {c}{x^2}\right )}{5 x^5}-\frac {2 b^2 \log \left (1+\frac {c}{x^2}\right )}{15 c x^3}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )}{10 x^5}-\frac {b^2 \log ^2\left (1+\frac {c}{x^2}\right )}{20 x^5}-\frac {2 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}-\frac {i b^2 \text {Li}_2\left (-1+\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {b^2 \text {Li}_2\left (-\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}+\frac {b^2 \text {Li}_2\left (\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}+\frac {b^2 \text {Li}_2\left (-1+\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}-\frac {\left (i b^2\right ) \int \frac {\log \left (1-\frac {i x}{\sqrt {c}}\right )}{x} \, dx}{5 c^{5/2}}+\frac {\left (i b^2\right ) \int \frac {\log \left (1+\frac {i x}{\sqrt {c}}\right )}{x} \, dx}{5 c^{5/2}}-\frac {\left (2 b^2\right ) \int \left (\frac {\tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{2 \left (\sqrt {c}-x\right )}-\frac {\tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{2 \left (\sqrt {c}+x\right )}\right ) \, dx}{5 c^{5/2}}-\frac {\left (2 b^2\right ) \int \left (-\frac {\tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{2 \left (\sqrt {-c}-x\right )}+\frac {\tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{2 \left (\sqrt {-c}+x\right )}\right ) \, dx}{5 c^{5/2}}\\ &=\frac {2 a b}{25 x^5}-\frac {2 a b}{15 c x^3}+\frac {2 a b}{5 c^2 x}-\frac {8 b^2}{15 c^2 x}+\frac {2 a b \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {4 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{15 c^{5/2}}-\frac {i b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {4 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{15 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {2 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{25 x^5}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{15 c x^3}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{5 c^2 x}-\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1-\frac {c}{x^2}\right )}{5 c^{5/2}}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{25 x^5}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{15 c x^3}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^2 x}+\frac {b \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^{5/2}}-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{20 x^5}-\frac {a b \log \left (1+\frac {c}{x^2}\right )}{5 x^5}-\frac {2 b^2 \log \left (1+\frac {c}{x^2}\right )}{15 c x^3}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )}{10 x^5}-\frac {b^2 \log ^2\left (1+\frac {c}{x^2}\right )}{20 x^5}-\frac {2 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}-\frac {i b^2 \text {Li}_2\left (-1+\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {b^2 \text {Li}_2\left (-\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {i b^2 \text {Li}_2\left (-\frac {i x}{\sqrt {c}}\right )}{5 c^{5/2}}+\frac {i b^2 \text {Li}_2\left (\frac {i x}{\sqrt {c}}\right )}{5 c^{5/2}}+\frac {b^2 \text {Li}_2\left (\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}+\frac {b^2 \text {Li}_2\left (-1+\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}-\frac {b^2 \int \frac {\tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{\sqrt {c}-x} \, dx}{5 c^{5/2}}+\frac {b^2 \int \frac {\tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{\sqrt {c}+x} \, dx}{5 c^{5/2}}+\frac {b^2 \int \frac {\tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{\sqrt {-c}-x} \, dx}{5 c^{5/2}}-\frac {b^2 \int \frac {\tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{\sqrt {-c}+x} \, dx}{5 c^{5/2}}\\ &=\frac {2 a b}{25 x^5}-\frac {2 a b}{15 c x^3}+\frac {2 a b}{5 c^2 x}-\frac {8 b^2}{15 c^2 x}+\frac {2 a b \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {4 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{15 c^{5/2}}-\frac {i b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {4 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{15 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {2 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{25 x^5}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{15 c x^3}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{5 c^2 x}-\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1-\frac {c}{x^2}\right )}{5 c^{5/2}}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{25 x^5}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{15 c x^3}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^2 x}+\frac {b \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^{5/2}}-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{20 x^5}-\frac {a b \log \left (1+\frac {c}{x^2}\right )}{5 x^5}-\frac {2 b^2 \log \left (1+\frac {c}{x^2}\right )}{15 c x^3}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )}{10 x^5}-\frac {b^2 \log ^2\left (1+\frac {c}{x^2}\right )}{20 x^5}-\frac {2 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {(1+i) \left (\sqrt {c}-x\right )}{\sqrt {c}-i x}\right )}{5 c^{5/2}}+\frac {2 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c} \left (\sqrt {-c}-x\right )}{\left (\sqrt {-c}-\sqrt {c}\right ) \left (\sqrt {c}+x\right )}\right )}{5 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c} \left (\sqrt {-c}+x\right )}{\left (\sqrt {-c}+\sqrt {c}\right ) \left (\sqrt {c}+x\right )}\right )}{5 c^{5/2}}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {(1-i) \left (\sqrt {c}+x\right )}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {2 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}-\frac {i b^2 \text {Li}_2\left (-1+\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {b^2 \text {Li}_2\left (-\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {i b^2 \text {Li}_2\left (-\frac {i x}{\sqrt {c}}\right )}{5 c^{5/2}}+\frac {i b^2 \text {Li}_2\left (\frac {i x}{\sqrt {c}}\right )}{5 c^{5/2}}+\frac {b^2 \text {Li}_2\left (\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}+\frac {b^2 \text {Li}_2\left (-1+\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}+2 \frac {b^2 \int \frac {\log \left (\frac {2}{1-\frac {i x}{\sqrt {c}}}\right )}{1+\frac {x^2}{c}} \, dx}{5 c^3}-\frac {b^2 \int \frac {\log \left (\frac {(1+i) \left (\sqrt {c}-x\right )}{\sqrt {c} \left (1-\frac {i x}{\sqrt {c}}\right )}\right )}{1+\frac {x^2}{c}} \, dx}{5 c^3}-\frac {b^2 \int \frac {\log \left (\frac {(1-i) \left (\sqrt {c}+x\right )}{\sqrt {c} \left (1-\frac {i x}{\sqrt {c}}\right )}\right )}{1+\frac {x^2}{c}} \, dx}{5 c^3}-2 \frac {b^2 \int \frac {\log \left (\frac {2}{1+\frac {x}{\sqrt {c}}}\right )}{1-\frac {x^2}{c}} \, dx}{5 c^3}+\frac {b^2 \int \frac {\log \left (\frac {2 \left (\sqrt {-c}-x\right )}{\left (-1+\frac {\sqrt {-c}}{\sqrt {c}}\right ) \sqrt {c} \left (1+\frac {x}{\sqrt {c}}\right )}\right )}{1-\frac {x^2}{c}} \, dx}{5 c^3}+\frac {b^2 \int \frac {\log \left (\frac {2 \left (\sqrt {-c}+x\right )}{\left (1+\frac {\sqrt {-c}}{\sqrt {c}}\right ) \sqrt {c} \left (1+\frac {x}{\sqrt {c}}\right )}\right )}{1-\frac {x^2}{c}} \, dx}{5 c^3}\\ &=\frac {2 a b}{25 x^5}-\frac {2 a b}{15 c x^3}+\frac {2 a b}{5 c^2 x}-\frac {8 b^2}{15 c^2 x}+\frac {2 a b \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {4 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{15 c^{5/2}}-\frac {i b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {4 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{15 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {2 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{25 x^5}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{15 c x^3}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{5 c^2 x}-\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1-\frac {c}{x^2}\right )}{5 c^{5/2}}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{25 x^5}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{15 c x^3}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^2 x}+\frac {b \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^{5/2}}-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{20 x^5}-\frac {a b \log \left (1+\frac {c}{x^2}\right )}{5 x^5}-\frac {2 b^2 \log \left (1+\frac {c}{x^2}\right )}{15 c x^3}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )}{10 x^5}-\frac {b^2 \log ^2\left (1+\frac {c}{x^2}\right )}{20 x^5}-\frac {2 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {(1+i) \left (\sqrt {c}-x\right )}{\sqrt {c}-i x}\right )}{5 c^{5/2}}+\frac {2 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c} \left (\sqrt {-c}-x\right )}{\left (\sqrt {-c}-\sqrt {c}\right ) \left (\sqrt {c}+x\right )}\right )}{5 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c} \left (\sqrt {-c}+x\right )}{\left (\sqrt {-c}+\sqrt {c}\right ) \left (\sqrt {c}+x\right )}\right )}{5 c^{5/2}}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {(1-i) \left (\sqrt {c}+x\right )}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {2 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}-\frac {i b^2 \text {Li}_2\left (-1+\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {i b^2 \text {Li}_2\left (1-\frac {(1+i) \left (\sqrt {c}-x\right )}{\sqrt {c}-i x}\right )}{10 c^{5/2}}-\frac {b^2 \text {Li}_2\left (-\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {i b^2 \text {Li}_2\left (-\frac {i x}{\sqrt {c}}\right )}{5 c^{5/2}}+\frac {i b^2 \text {Li}_2\left (\frac {i x}{\sqrt {c}}\right )}{5 c^{5/2}}+\frac {b^2 \text {Li}_2\left (\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}+\frac {b^2 \text {Li}_2\left (-1+\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}+\frac {b^2 \text {Li}_2\left (1-\frac {2 \sqrt {c} \left (\sqrt {-c}-x\right )}{\left (\sqrt {-c}-\sqrt {c}\right ) \left (\sqrt {c}+x\right )}\right )}{10 c^{5/2}}+\frac {b^2 \text {Li}_2\left (1-\frac {2 \sqrt {c} \left (\sqrt {-c}+x\right )}{\left (\sqrt {-c}+\sqrt {c}\right ) \left (\sqrt {c}+x\right )}\right )}{10 c^{5/2}}-\frac {i b^2 \text {Li}_2\left (1-\frac {(1-i) \left (\sqrt {c}+x\right )}{\sqrt {c}-i x}\right )}{10 c^{5/2}}+2 \frac {\left (i b^2\right ) \text {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1-\frac {i x}{\sqrt {c}}}\right )}{5 c^{5/2}}-2 \frac {b^2 \text {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1+\frac {x}{\sqrt {c}}}\right )}{5 c^{5/2}}\\ &=\frac {2 a b}{25 x^5}-\frac {2 a b}{15 c x^3}+\frac {2 a b}{5 c^2 x}-\frac {8 b^2}{15 c^2 x}+\frac {2 a b \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {4 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{15 c^{5/2}}-\frac {i b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {4 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )}{15 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right )^2}{5 c^{5/2}}+\frac {2 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{25 x^5}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{15 c x^3}-\frac {b^2 \log \left (1-\frac {c}{x^2}\right )}{5 c^2 x}-\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1-\frac {c}{x^2}\right )}{5 c^{5/2}}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{25 x^5}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{15 c x^3}-\frac {b \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^2 x}+\frac {b \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )}{5 c^{5/2}}-\frac {\left (2 a-b \log \left (1-\frac {c}{x^2}\right )\right )^2}{20 x^5}-\frac {a b \log \left (1+\frac {c}{x^2}\right )}{5 x^5}-\frac {2 b^2 \log \left (1+\frac {c}{x^2}\right )}{15 c x^3}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (1+\frac {c}{x^2}\right )}{5 c^{5/2}}+\frac {b^2 \log \left (1-\frac {c}{x^2}\right ) \log \left (1+\frac {c}{x^2}\right )}{10 x^5}-\frac {b^2 \log ^2\left (1+\frac {c}{x^2}\right )}{20 x^5}-\frac {2 b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {(1+i) \left (\sqrt {c}-x\right )}{\sqrt {c}-i x}\right )}{5 c^{5/2}}+\frac {2 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c} \left (\sqrt {-c}-x\right )}{\left (\sqrt {-c}-\sqrt {c}\right ) \left (\sqrt {c}+x\right )}\right )}{5 c^{5/2}}-\frac {b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {2 \sqrt {c} \left (\sqrt {-c}+x\right )}{\left (\sqrt {-c}+\sqrt {c}\right ) \left (\sqrt {c}+x\right )}\right )}{5 c^{5/2}}+\frac {b^2 \tan ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (\frac {(1-i) \left (\sqrt {c}+x\right )}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {2 b^2 \tanh ^{-1}\left (\frac {x}{\sqrt {c}}\right ) \log \left (2-\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}+\frac {i b^2 \text {Li}_2\left (1-\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {i b^2 \text {Li}_2\left (-1+\frac {2 \sqrt {c}}{\sqrt {c}-i x}\right )}{5 c^{5/2}}-\frac {i b^2 \text {Li}_2\left (1-\frac {(1+i) \left (\sqrt {c}-x\right )}{\sqrt {c}-i x}\right )}{10 c^{5/2}}-\frac {b^2 \text {Li}_2\left (-\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {i b^2 \text {Li}_2\left (-\frac {i x}{\sqrt {c}}\right )}{5 c^{5/2}}+\frac {i b^2 \text {Li}_2\left (\frac {i x}{\sqrt {c}}\right )}{5 c^{5/2}}+\frac {b^2 \text {Li}_2\left (\frac {x}{\sqrt {c}}\right )}{5 c^{5/2}}-\frac {b^2 \text {Li}_2\left (1-\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}+\frac {b^2 \text {Li}_2\left (-1+\frac {2 \sqrt {c}}{\sqrt {c}+x}\right )}{5 c^{5/2}}+\frac {b^2 \text {Li}_2\left (1-\frac {2 \sqrt {c} \left (\sqrt {-c}-x\right )}{\left (\sqrt {-c}-\sqrt {c}\right ) \left (\sqrt {c}+x\right )}\right )}{10 c^{5/2}}+\frac {b^2 \text {Li}_2\left (1-\frac {2 \sqrt {c} \left (\sqrt {-c}+x\right )}{\left (\sqrt {-c}+\sqrt {c}\right ) \left (\sqrt {c}+x\right )}\right )}{10 c^{5/2}}-\frac {i b^2 \text {Li}_2\left (1-\frac {(1-i) \left (\sqrt {c}+x\right )}{\sqrt {c}-i x}\right )}{10 c^{5/2}}\\ \end {align*}

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Mathematica [F]
time = 1.95, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (a+b \tanh ^{-1}\left (\frac {c}{x^2}\right )\right )^2}{x^6} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Integrate[(a + b*ArcTanh[c/x^2])^2/x^6,x]

[Out]

Integrate[(a + b*ArcTanh[c/x^2])^2/x^6, x]

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Maple [F]
time = 0.07, size = 0, normalized size = 0.00 \[\int \frac {\left (a +b \arctanh \left (\frac {c}{x^{2}}\right )\right )^{2}}{x^{6}}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+b*arctanh(c/x^2))^2/x^6,x)

[Out]

int((a+b*arctanh(c/x^2))^2/x^6,x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*arctanh(c/x^2))^2/x^6,x, algorithm="maxima")

[Out]

1/15*(c*(6*arctan(x/sqrt(c))/c^(7/2) - 3*log((x - sqrt(c))/(x + sqrt(c)))/c^(7/2) - 4/(c^2*x^3)) - 6*arctanh(c
/x^2)/x^5)*a*b - 1/20*b^2*(log(x^2 - c)^2/x^5 + 5*integrate(-1/5*(5*(x^2 - c)*log(x^2 + c)^2 + 2*(2*x^2 - 5*(x
^2 - c)*log(x^2 + c))*log(x^2 - c))/(x^8 - c*x^6), x)) - 1/5*a^2/x^5

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*arctanh(c/x^2))^2/x^6,x, algorithm="fricas")

[Out]

integral((b^2*arctanh(c/x^2)^2 + 2*a*b*arctanh(c/x^2) + a^2)/x^6, x)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (a + b \operatorname {atanh}{\left (\frac {c}{x^{2}} \right )}\right )^{2}}{x^{6}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*atanh(c/x**2))**2/x**6,x)

[Out]

Integral((a + b*atanh(c/x**2))**2/x**6, x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*arctanh(c/x^2))^2/x^6,x, algorithm="giac")

[Out]

integrate((b*arctanh(c/x^2) + a)^2/x^6, x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (a+b\,\mathrm {atanh}\left (\frac {c}{x^2}\right )\right )}^2}{x^6} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*atanh(c/x^2))^2/x^6,x)

[Out]

int((a + b*atanh(c/x^2))^2/x^6, x)

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